数列{an}满足a1=1.5,an+1=an²-an+1（n∈N﹢）,则m=1/a1+1/a2+...+1/a

一直数列{An}满足A1=1/2,A1+A2+…+An=n^2An 已知数列{an}中满足a1=1,a(n+1)=2an+1 (n∈N*),证明a1/a2+a2/a3+…+an/a(n+1 已知数列{an}满足a1=1，a2=2，an+2=an+an+12，n∈N*． 已知数列{An}满足A1=0.5,A1+A2+…+An=n^2An(n∈N*),试用数学归纳法证明:An=1/n(n+1 已知数列an满足an=1+2+...+n,且1/a1+1/a2+...+1/an 给定数列an={a1,a2,a3.an},bn=a（n+1）-an 数列an满足a1=3/2,a(n+1)=an^2-an+1则m=1/a1+1/a2````1/a2009整数部分是 设数列{an}满足a1+3a2+3²a3+...+3^(n-1)an=n/3,n∈N+*.（1）求数列{an} 数列{an}满足a1=3/2,an+1=an^2-an+1(n属于正整数),则m=1/a1+1/a2+……+1/a200 设数列{an}满足a1+3a2+3^2a3+.3^n-1×an=n/3,a∈N+. 已知数列{an}满足an+1=an+n,a1等于1,则an=? 已知数列{an}满足a1=100，an+1-an=2n，则a