switch(a+b) { case 1 : case 3 : y = a + b ; break ; case 0 :
switch(a*a+b*b); { case 3 :case 1 :y=a+b; break; case 0 :y=b
switch(a){ case 'a':case 'b':case 'c':输出语句; break; }这是运行的哪一个
int x=1,a=0,b=0; switch(x) { case 0:b++; case 1:a++; case 2:
main() { int x=1,a=0,b=0; switch(x){ case 0:b++; case 1:a++;
{int x=1,a=0,b=0;switch(x){ case 0:b++; case 1:a++; case 2:a
int x=1,a=0,b=0;switch (x){case 0:b++;case 1:a++;case 2:a++;
#include main() { int x=1,y=0,a=0,b=0; switch(x) { case 1: s
#include main() { int x=1,y=0,a=0,b=0; switch(x) { case
main() {int a=2,b=7,c=5; switch(a>0) {case 1:switch(b0)
关于一道C语言的问题int x=1,a=0,b=0; switch(x) { case 0:b++; case 1:a+
do{ switch case‘a':case'A':case'e':case'E':case'i':case'I':c
int k=2; switch(k+1) {case 3:k+=1; case 4:k--;break; case 5: