3^log9(25)+16^log4(2)-(根号7)^log7(9)+(-1)^log2(1)
log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(2
[log2(3)+log4(9)][log3(4)+log9(2)]等于
log2 根号2+log9 27+4^log4 13=?
log2^根号下2+log9^27+4^(log4^13)
(log3,4+log9,4)log4,3—log2,2根号2 这怎么解答了
计算(log2 3+log4 9+log8 27+……+log2^n 3^n)log9 n次根号3
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log2
(log4^3+log8^3)(log3^2+log9^2)+log2^(32)的1/4次方
(log2 3+log4 9.+log8 27+.+log(2^n底)(3^n))log9 n次根号32
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(