已知(x-2)(x²-6x-9)=x(x-5)(x-3),求6x的算术平方根
解方程 (3x+1)(3x-1)=(x+2)(9x-4) 2(x-3)(x-2)-(x+3)²=(x-1)(x
f(x)=x²+3x|x-2|
x²+3x+9/(x²-27)+6x/(9x-x²)-(x-1)/(6+2x)
4x²-{-3x²-[5x-x²-(2x²-x)]+4x},其中x=½
(2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3)
(x+1)(x+2)(x+3)x+1=0则3x²+9x+7
不等式|(x+3)/x|>(x+3)/x,不等式(x²-9)/(x-2)>0
①2(x+3)(x-3)=x²+(x-1)(x+1)+2x
已知f(x)={x/2,x>=0 -x²+3x,x=0
解方程(x²-2)+2x²(x+3)-3x-(5x-7)=x(3x²-9x+17)+2
9x+6x²-3(x-2/3x²),其中x=-2 1/4(-4x²+2x-8)-(1/2x