作业帮一道物理判断题 学渣求大神帮帮看
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一道物理判断题 学渣求大神帮帮看
This problem has analogies in the game of pool.Puck 1 slides on a horizontal,frictionless surface with velocity v and collides elastically with stationary puck 2; each puck has the same mass, m.The pucks move off with velocities v1 and v2,as shown.The angles θ1 and θ2 are measured relative to the initial direction of puck 1.
Answer true or false to the statements below; e.g.,if the first one is true and the rest are false,enter TFFFF.
v2 = v1cos2θ1+v2cos2θ2
This problem has analogies to pool because pool balls have equal mass and roll without friction.[As long as rotational KE of pool balls is neglected,the analogy is perfect.]
In this problem,kinetic energy is conserved but linear momentum is not conserved.
If a+b = c for three non-zero vectors,and a2+b2 = c2,then the angle between a and b is 90°.
v = v1cos2θ1+v2cos2θ2
This problem has analogies in the game of pool.Puck 1 slides on a horizontal,frictionless surface with velocity v and collides elastically with stationary puck 2; each puck has the same mass, m.The pucks move off with velocities v1 and v2,as shown.The angles θ1 and θ2 are measured relative to the initial direction of puck 1.
Answer true or false to the statements below; e.g.,if the first one is true and the rest are false,enter TFFFF.
v2 = v1cos2θ1+v2cos2θ2
This problem has analogies to pool because pool balls have equal mass and roll without friction.[As long as rotational KE of pool balls is neglected,the analogy is perfect.]
In this problem,kinetic energy is conserved but linear momentum is not conserved.
If a+b = c for three non-zero vectors,and a2+b2 = c2,then the angle between a and b is 90°.
v = v1cos2θ1+v2cos2θ2
FTFT
这是非对心碰撞
需要把v1正交分解到沿圆心连线方向 v1cosθ2和垂直于圆心连线方向 v1cosθ1
其中沿连线方向交换动量,由于质量相等,就是交换速度,
所以v2= v1cosθ2
最后一个等式v表示什么,没看到,所以无法判断
这是非对心碰撞
需要把v1正交分解到沿圆心连线方向 v1cosθ2和垂直于圆心连线方向 v1cosθ1
其中沿连线方向交换动量,由于质量相等,就是交换速度,
所以v2= v1cosθ2
最后一个等式v表示什么,没看到,所以无法判断