[(x+2y)2-(x+y)(3x+y)-2y2 ]÷(2x
x/x-y*y^2/x+y-x^3y2/x^4-y^4/x^2/x^2+y^2
求解初中数学题(x-y)-2(y-x) 2(x-y)-8(y-x) x(a-3)-(3-a) (x2-y2)-3(x+y
1、x(x-y)(x+y)-x(x+y)^2
先化简再求值[(x+y)2-(x+y)(x+3y)-4y2]÷2y,其中x=-2,y=12
化简求值:[(x+2y)2-(x+y)(3x-y)-5y2]÷2x,其中x=-2,y=12
【-(-2x^2y)^3】^2*(-3x^3y2)
有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【-
已知[(x2+y2)-(x-y)2+2y(x-y)]÷4y=1,求4x/4x2-4y2-1/2x+y的值,
化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方
【x-3y][x+y]-[x-2y][x +2y]-[x-y
[(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y)
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y