用C语言表达求1!+2!+……+n!(n
求满足不等式C(n,1)+2C(n,2)+……+nC(n,n)
组合:C(n,0)+C(n,1)+……+C(n,n)=n^2
计算:C(1,n)+2C(2,n)+3C(3,n) + … + nC(n,n)
证明C(0,n)^2+C(1,n)^2+……+C(n,n)^2=C(n,2n)
C(n.0)+2C(n.1)+4C(n.2)+C(n.2)+C(n.3)…+C(n.n)=?
An=C(1,n)a1+C(2,n)a2+…C(n,n)an,
.设计一程序,求n的阶乘n!(n!=1*2*……*n).c语言
(1+2)^n = C(n,0) +2C(n,1) +2^2C(n,2) +2^3C(n,3)+……+2^nC(n,n)
求极限 lim n[1/(n^2+1)+1/(n^2+2^2)+……+1/(n^n+n^n)] (n趋向于无穷大,n^n
C语言用递归求函数的第n项f(n) = 1×2 + 2×3 + 3×4 + …… + n×(n+1)
求极限Xn=n/(n^2+1)+n/(n^2+2)+n/(n^2+3)+……+n/(n^2+n),
求值:C(n,0)+2C(n,1)+(2^2)C(n,2)+…+(2^n)C(n,n)(数学高手请进)(要有具体过程,