若数列{an}满足a1=15,3a
若数列an满足a1=2,a(n+1)=3an+2,求数列的通项公式
若数列{An}满足A1=1,A(n+1)=An/(2An + 1)
已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an
已知数列an满足a1=1,a(n+1)=an/(3an+1) 求数列通项公式
已知数列{an}满足a1=4/3,2-a(n+1)=12/an+6
【高中数学题】已知数列{an}满足a1=1,a(n+1)=3an+1
【高考】若数列{an}满足,a1=1,且a(n+1)=an/1+an,证明,数列{1/an}为等差数列,并求出数列{an
已知两个等比数列{an},{bn}满足a1=a(a>0),b1-a1=1,b2-a2=2,b3-a3=3,若数列{an}
已知数列{an}满足a1=1;an=a1+2a2+3a3+...+(n-1)a(n-1);
若数列{An},满足关系a1=2,an+1=3an+2,求数列的通项公式
已知数列{An}满足A1=1,A=3(n-1)+A(n>/2)
已知数列{an}满足a1=1,2a(n+1)an+3a(n+1)+an+2=0.