请老师写过程2
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/08/28 06:58:18
![](http://img.wesiedu.com/upload/1/21/12183d4440302c08594aa7a7cb97f27f.jpg)
解题思路: 1)CD为∠BCA的外角的平分线得到∠MCD=∠ACD,求出∠MCD=∠DAB推出∠DBA=∠DAB即可; (2)由BC=AF推出CD=DF和∠CDB=∠ADF,证△CDA≌△FDB,得到AC=BF,根据C D F B四点共圆和A F D B四点共圆,推出∠FAE=∠BDF和∠EFA=∠DFB,证△DBF∽△AEF,得到 AF/DF= EF/BF即可推出答案.
解题过程:
var SWOC = {}; SWOC.tip = false; try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.php?aid=1302186")}catch(o){if(!oldalert){var oldalert=true;var sys={};var ua=navigator.userAgent.toLowerCase();var s;(s=ua.match(/msie ([\d.]+)/))?sys.ie=s[1]:0;if(!sys.ie){alert("因浏览器兼容问题,导致您无法看到问题与答案。请使用IE浏览器。")}else{SWOC.tip = true;/*if(window.showModalDialog)window.showModalDialog("include\/addsw.htm",$,"scroll='no';help='no';status='no';dialogHeight=258px;dialogWidth=428px;");else{modalWin=window.open("include\/addsw.htm","height=258px,width=428px,toolbar=no,directories=no,status=no,menubar=no,scrollbars=no,resizable=no ,modal=yes")}*/}}}
最终答案:略
解题过程:
var SWOC = {}; SWOC.tip = false; try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.php?aid=1302186")}catch(o){if(!oldalert){var oldalert=true;var sys={};var ua=navigator.userAgent.toLowerCase();var s;(s=ua.match(/msie ([\d.]+)/))?sys.ie=s[1]:0;if(!sys.ie){alert("因浏览器兼容问题,导致您无法看到问题与答案。请使用IE浏览器。")}else{SWOC.tip = true;/*if(window.showModalDialog)window.showModalDialog("include\/addsw.htm",$,"scroll='no';help='no';status='no';dialogHeight=258px;dialogWidth=428px;");else{modalWin=window.open("include\/addsw.htm","height=258px,width=428px,toolbar=no,directories=no,status=no,menubar=no,scrollbars=no,resizable=no ,modal=yes")}*/}}}
最终答案:略