if(y>z)p2[14],tmp3[14],tmp4[14];
prefresh(pad,0,0,0,if(AIeat(tmp3,tmp2,tmp4,1)==0)return0;
x+y+z=14,x'+y'+z'=15,(x-x')+(y+y')+z*z'=16,已知xyz为自然数,求x,y,z的
2x+y+z=17 x+2z+y=14 x+z+2y=13 求:xyz
x+z=y 7*x=y+z+2 x+y+z=14 解这个方程组、
x+2y+3z=14 2x+y+z=7 3x+y+2z=11
3x+2y+z=14 x+y+2z+-3 2x+3y-z=1
已知2x+5y+4z=15.7x+y+3z=14 则x+y+z=?
解三元一次方程组 x+y=12 x+y+z=10 z-y-z=14 急
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
[3x+2y+z=14,x+y+z=10,2x+3y-z=1]
x+2y+3z=14 2x+y+z=7 3x+y+2z=11 求x y z
已知x²+y²+z²-2x+4y-6z+14=0,求x+y-z/x+y+z的值