(2x-1)²-9x²=0
解方程 x(x+1)-x-9=0 x²-2x=224 x(x-2)=2(2-x) x²-(2(√2)
已知函数f(x)=x²+x+1,x≥0;2x+1,x
(x+1)(x+2)(x+3)x+1=0则3x²+9x+7
已知x²-3=0,求代数式x(x+1)²-x(x²+x)-x-9的值
已知X不等于0,且M=(X²+2X+1)(X-2X+1),N=(X²+X+1)(x²-X+
解方程(x²-3x)/(x²-1)+(2x-1)/(x-1)=0
解方程 (3x+1)(3x-1)=(x+2)(9x-4) 2(x-3)(x-2)-(x+3)²=(x-1)(x
解方程 x(x+1)(x²-2x-4)=0 x³-2x+1=0 x的4次方+8x³+14x
设f (x)={2x+1(x≥0),x²+4(x
5/x²+x-1/x²-x=0
2x²+3x+1=0 求x
x²+3x+9/(x²-27)+6x/(9x-x²)-(x-1)/(6+2x)