计算:(5+1)(5^2+1)(5^4+1)...(5^256+1)+1
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/10/04 06:19:59
计算:(5+1)(5^2+1)(5^4+1)...(5^256+1)+1
原式=(1/4)×(5-1)(5+1)(5²+1)(5^4+1)······(5^256+1)+1
=(1/4)×(5²-1)(5²+1)(5^4+1)······(5^256+1)+1
=(1/4)×(5^4-1)(5^4+1)······(5^256+1)+1
=······
=(1/4)×(5^256-1)(5^256+1)+1
=(1/4)(5^512-1)+1
=(5^512+3)/4
再问: 最后两步不懂,求解释
再答: (5^256-1)(5^256+1)=5^512-1,这仍然是平方差
(1/4)(5^512-1)+1=5^512/4-1/4+1=5^512/4+3/4=(5^512+3)/4
=(1/4)×(5²-1)(5²+1)(5^4+1)······(5^256+1)+1
=(1/4)×(5^4-1)(5^4+1)······(5^256+1)+1
=······
=(1/4)×(5^256-1)(5^256+1)+1
=(1/4)(5^512-1)+1
=(5^512+3)/4
再问: 最后两步不懂,求解释
再答: (5^256-1)(5^256+1)=5^512-1,这仍然是平方差
(1/4)(5^512-1)+1=5^512/4-1/4+1=5^512/4+3/4=(5^512+3)/4
先观察,后计算(1)计算自然数1,2,3,.,999的和(2)计算1+3+5+...+297+299(3)计算100-9
计算:(1+5
计算 (-1)+(+2)+(-3)+(+4)+(-5)+…+(-2010)+(+2011)
简便计算5/6-(3/4-1/2)=
计算(12345+23451+34512+45123+51234)/(1+2+3+4+5)脱式,简便计算,急.
3/5-(1/2-1/4)计算,
1、3/5×11/13×1/3,在计算时,应用()律能使计算简便.
用简便计算计算下面这题;24*(5/12+1/15)*15
1计算:1+3+5+…+(2n+1)
计算1+3+5+7…+(2n+1)
计算:(1)(-1/15+2/3-5/6)×|-30|
计算:(-2)+(-1)-(-5)-|-3| 要过程