一元一次方程(1)4x-7=-2(x-1) (2)1-2【1-(2-x)】=x (3)50%x-3=2x+6 (4)10
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
2/x+3x=2/x-7和x²-4x=x(x-1)-3是不是一元一次方程?怎么判断?
解一元一次方程2(4x-3)-5x=6(3x-2)=2(x+1),
解一元一次方程~2.5[1-3x+二分之一(4+3x)]=2-x
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
6/(x+1)=(x+5)/[x(x+1)] (3-x)/(x-4)+1/(4-x)=1 2/(1+x)-3/(1-x)
1、x*(x+3)*(x+6)*(x+9)=68040 2、x*(x+1)*(x+2)*(x+3)*(x+4)=5544
求解一元一次方程:(1)7x-[x-1/2(x-1)]=2/3(x-1)(2)3/4[4/3(1/2x-1/4)-16]
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|