int i;int x[3] [3]={1,2,3,4,5,6,7,8,9}
int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int **p; p=(int**)a;
main(){int x[]={1,2,3,4,5,6,7,8,9}int s,i,*p;s=0;p=&x[0];fpr
#define N 10 main() { int a[N]={1,2,3,4,5,6,7,8,9,10} int i,
int a[3][3]={{1,2,3},{4,5},{6}}; int i,
int main() { int a[9] = {1,2,3,4,5,6,7,8,9}; int b[9] = {1,2
以下程序的输出结果是_____.int i,x[ ] [ ]={{1,2,3},{4,5,6},{7,8,9}}
main() { int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int *b; b=a;
解释下代码的含义int[] numbers = new int[] { 6,4,3,2,9,1,7,8,5 };List
int j;int x[3][3]={1,2,3,4,5,6,7,8,9}; for (j=2; j>=0; j--)
main( ) { int i,x[3][3]={1,2,3,4,5,6,7,8,9}; for(i=0;i
#include void main(){int k1=1;int k2=2;int k3=3;int x=15;if(
Struct Struct st {int x;int *y;}*pt; Int a[]={1,2},b[]={3,4}