sin(x/2) = 2/3 [0≤x≤pi/2] cosx?tanx?sin(x/4)
已知函数f(x)=cos(2x-pi/3)+2sin(x-pi)*sin(x+pi/4)
由sin(2x+pi/4)得到cosx的图象
已知(sinx+cosx)/(sinx-cosx)=3,求tanx,2sin²x+(sinx-cosx)&su
已知Sin(2x+pi/3)=1/3,求Sin(5Pi/6-4x),
求化简(sinx+tanx)/cos^2x+sin^2x+cosx
已知函数f(x)=sin(2x+pi/3)+sin(2x-pi/3)+2cosx^2-1,x∈R.
sin^2x*tanx+cos^2x*cotx+2sinx*cosx=tanx+cotx
1-2sinx cosx /COS^2X-SIN^2X =1-tanx/1+tanx 求证
提问数学难题求证:sin^2x*tanx+cos^2x/tanx+2sinx*cosx=tanx+1/tanx
已知tanx=1/2,求sin x-cos x/2sinx+3cosx的值
证明tanx-sinx/sin^3(x)=1-cosx/cosxsin^2(x)
为什么|sin(2x+pi)|=|sin(2x)|呢?