用整式除法计算,1.(5x^2y^3)^2÷(25x^4y^5) 2.(x+y)^3÷(x+y) 3.(7a^5b^3c
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/09/04 09:03:04
用整式除法计算,
1.(5x^2y^3)^2÷(25x^4y^5)
2.(x+y)^3÷(x+y)
3.(7a^5b^3c^5)÷(14a^2b^3c)
4.(8a^4b^3c)÷(2a^2b^3)·(-2/3a^3bc^2)
5.(3x^2y)·(-15xy^3)÷(-9x^4y^2)
用整式除法计算,
1.(5x^2y^3)^2÷(25x^4y^5)
2.(x+y)^3÷(x+y)
3.(7a^5b^3c^5)÷(14a^2b^3c)
4.(8a^4b^3c)÷(2a^2b^3)·(-2/3a^3bc^2)
5.(3x^2y)·(-15xy^3)÷(-9x^4y^2)
用整式除法计算,
整式的除法,就是将除号变成分数线,然后,分子与分母进行约分即可.
1、原式=25X^4y^6/25x^4y^5
=y
2、原式=.(x+y)^3/(x+y)
=.(x+y)^2
3、原式=(7a^5b^3c^5)/(14a^2b^3c)
=a^3c^4/2
4、原式=4a^2c*(-2/3a^3bc^2)
= -8/3a^5bc^3
5、原式=5x^3y^4/x^4y^2
=5y^2/x
1、原式=25X^4y^6/25x^4y^5
=y
2、原式=.(x+y)^3/(x+y)
=.(x+y)^2
3、原式=(7a^5b^3c^5)/(14a^2b^3c)
=a^3c^4/2
4、原式=4a^2c*(-2/3a^3bc^2)
= -8/3a^5bc^3
5、原式=5x^3y^4/x^4y^2
=5y^2/x
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