来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/08/27 02:54:27
求解答第二十七题
![](http://img.wesiedu.com/upload/c/9e/c9e10bd0d4b032311ac689ba46293428.jpg)
(1)原式=(1/2)*(3/2)*(2/3)*(4/3)*(3/4)*(5/4)*……*(99/100)*(101/100)【中间的互为倒数,相互约分,积为1】==(1/2)*(101/100)=101/200
(2)原式==(1/2)*(3/2)*(2/3)*(4/3)*(3/4)*(5/4)*……*((n-1)/n)*((n+1)/n)【中间的互为倒数,相互约分,积为1】==(1/2)*((n+1)/n)=(n+1)/(2n)