请各位数学挚友帮帮忙···(1)a²-2a+1和2a-a²-1 (2)a-3和-(a-2)(3-a)
化简求值;(a-2/a²-4a+4)-(a+3/a²)的和,除以1/a²-3a 其中a=4
求和:1,a+a^2,a^3+a^4+a^5,a^6+a^7+a^8+a^9,···(a不等于0)
已知a-1/a=3,求a-1/a和a^2-1/a^2
(a 1)(a 2)(a 3)(a
1a^2-3a+1=0,求a+1/a ,a^2+1/a^2和(a-1/a)^2的值(写过程)
计算:a²+9-6a分支2a²-4a-6/(4a+8)×4+3a-a²分支6+a-a
已知实数a满足a²+4a-8=0,求(1/a+1)-(a+3/a²-1)·(a²-2a+1
(高一集合)已知A={2,4,a*a*a-2a*a-a+7},B={1,a+3,a*a-2a+2,a*a*a+a*a+3
a(a-1)(a-2)(a-3)(a-4)因式分解
1/a+1-a+2/a²-1·a²-2a+1/a²+4a+4.
(a- 2a/a)÷1-a² / a²+a
计算:(2a+3)(a²+a-1)