1.X+Y+Z=6X+2Y+3Z=12182.X+Y=2572X×2=96Y3.X+Y=682X+4Y=208

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) (x+y-z)(x-y+z)= 如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai 1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6 x/2=y/3=z/5 x+3y-z/x-3y+z X+Y+Z=? f(x,y,z,w)=x*(x+y)*(x+y+z)*(x+y+z+w) x,y,z为实数 且(y-z)^2+(x-y)^2+(z-x)^2=(y+z-2x)^2+(x+z-2y)^2+(x+y x,y,z为实数且(y-z)平方+(x-y)平方+(z-x)平方=(y+z-2x)平方+(z+x-2y)平方+(x+y- (x+y-z)^2-(x-y+z)^2=? ①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z-