已知全集U=R,集合M={y|y=2x+1},N={x|y=lg(3-x)},则(CUM)∩N=( )
设全集U=R,集合M={y|y=x2+2},集合N={y|y=3x,x属于U},则MUN等于()
设全集U=R,集合M={x/x≥2},N={y/y>0},则CuM与CuN的包含关系是
设全集U=坐标的形式,X,Y都属于实数,集合M的X,Y满足y-3/x-2=1,N中X,Y满足x-3=x-2那么CuM∩N
设全集U={(x,y)|x,y∈R},集合M={(x,y)|y−3x−2=1},N={(x,y)|y≠x+1},则∁U(
设集合M={y│-1≤y≤2},N={y│y≥0}全集U=R,求(CuM)交(CuN).
设全集U={(x,y)|x,y属于R},集合M={(x,y)|(y-3)除以(x-2)=1},N={(x,y)|y不等于
设全集U={(x,y)|x,y属于R},集合M={(x,y)|(y+2)除以(x-2)=1},N={(x,y)|y不等于
已知全集u=R,集合M={x,|x-2|≥3},则CuM=
设全集u=R,集合M={y=|y=x²+2,x∈U},集合N={y|y=3x,x∈U},则M∩N等于
若全集I={(x,y)|x,y∈R},集合M={(x,y)|(y-3)/(x-2)},N{(x,y)|y=x=1},则(
设全集U={(x,y)|x,y∈R},集合M={(x,y)|y+2x−2=1},N={(x,y)|y≠x-4},那么(∁
设全集U=R,集合M={x|y=根号(1-x2),则CuM=