[(-2ab)^2*(0.5a^3b^2c)]^3/[-8a(a^2b)^5
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[(-2ab)^2*(0.5a^3b^2c)]^3/[-8a(a^2b)^5
[(-2ab)^2*(0.5a^3b^2c)]^3/[-8a(a^2b)^5]
=[4a^2b^2*0.5a^3b^2c]^3/[-8a*a^(2*5)*b^5]
=[(4*0.5)*a^(2+3)*b^(2+2)c]/[-8*a^(1+10)*b^5]
=[2*a^5b^4c]^3/[-8*a^11*b^5]
=[2^3*a^(5*3)*b^(4*3)*c^3]/[-8*a^11*b^5]
=[8*a^15*b^12*c^3]/[-8*a^11*b^5]
=(8÷-8)*a^(15-11)*b^(12-5)*c^3
=-a^4b^7c^3
=[4a^2b^2*0.5a^3b^2c]^3/[-8a*a^(2*5)*b^5]
=[(4*0.5)*a^(2+3)*b^(2+2)c]/[-8*a^(1+10)*b^5]
=[2*a^5b^4c]^3/[-8*a^11*b^5]
=[2^3*a^(5*3)*b^(4*3)*c^3]/[-8*a^11*b^5]
=[8*a^15*b^12*c^3]/[-8*a^11*b^5]
=(8÷-8)*a^(15-11)*b^(12-5)*c^3
=-a^4b^7c^3
(12a^3b^2c^3-6a^2b+3ab)/3ab= [(a+b)^5-(a+b)^3]/(a+b)^3=
已知a,b,c是实数,求证a*a+b*b+c*c>=ab+3b+2c
向量AB=5/11a-b,向量BC=2a-8a,向量CD=3(a-b),求证:A B C三点共线
1.A=3a^2+4ab-1/2b^2,B=5a^2-2ab,且2A-B+C=0(A不等于a,B不等于b,C不等于c),
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
已知:A=-2ab,B=3ab(a+b),C=2a^2b*3ab^3,求3A*B-1/2A*C
(a-b)(b-c)(c-a)/(b-a)(a-c)2(c-b)3
已知A=3A^2B+3AB^2+B^4,B=-8AB^2+2A^2B+C^4,求A-2B
已知a+b/a-b=b+c/2(b-c)=c+a/3(c-a),求证:8a+9b+5c=0
(a+b)/(a-b)=(b+c)/2(b-c)=(c+a)/3(c-a),abc互不相等,证8a+9b+5c=o
证明:8(a+b+c)^3-(b+c)^3-(c+a)^3-(a+b)^3=3(2a+b+c)(a+2b+c)(a+b+
因式分解a^+b^+2a^b+2ab^+a^+b^+3ab+a+b