if 2.0 mol of HF are exposed to 4.5 mol of SiO2,which is the

来源：学生作业帮编辑：作业帮分类：英语作业时间：2024/09/29 20:50:55

if 2.0 mol of HF are exposed to 4.5 mol of SiO2,which is the limiting reactant?
SiO2(s)+4h=HF(g)→SiF4(g)+2H2O(I)

HF is the limiting reactant
再问：解题过程呢？
再问：公式是什么？
再答： Reaction SiO2(s)+ 4HF(g)→SiF4(g)+2H2O(l) 1 4 4.5 mol x mol case 1 y mol 2.0 mol case 2 x=18 mol>2.0 mol case 1 is unreasonable y=0.5 mol < 4.5 mol case 2 is reasonable, so HF is the limiting reactant
再问：

再问：那这一题怎么做？
再问：

再答： Reaction: 2KClO3 → 2KCl + 3O2 2 2 12.0g÷122.5g/mol x x=12.0÷122.5×2÷2 mol=0.0980 mol
再问：那两个22是什么？
再答： mole ratio 反应摩尔比
再问：看得不太懂，可以麻烦把解题思路用中文写一下吗？谢谢了
再答：反应方程式是 2KClO3 → 2KCl + 3O2 由反应式可得氯酸钾和氯化钾的反应摩尔比是（反应方程式可以理解成2个氯酸钾分子的反应，也可以理解成2mol氯酸钾分子的反应） 2 2 实际反应中的摩尔数是 12.0g÷122.5g/mol （质量到摩尔的换算） x （设定氯化钾生成x摩尔）联立得2/（12.0÷122.5）=2/x x=12.0÷122.5×2÷2 mol=0.0980 mol（保留3位有效数字）
再问：哦，懂了，谢谢
再问：请问下为什么你会用美国人的算法，和英语回答去做题目呢？
再答：美国人的算法和英语回答.... 我只是以为你们要求用英文回答，至于美国人的算法是什么样子的？....
再问：就是和你刚刚的差不多
再问：以为你是留学生
再问：我刚刚的问题都是初中教的？
再答：内容是初中的，英语不是
再问：哦

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