sin(-19π/6)=;sin(-16π/3)=;cos(-79π/6)=;tan(-26π/3)=;sin(15π/
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/08/29 05:53:28
sin(-19π/6)=;sin(-16π/3)=;cos(-79π/6)=;tan(-26π/3)=;sin(15π/4)=;
cos(-60°)-sin(-210°)=?
cos(-60°)-sin(-210°)=?
sin(-19π/6)=-sin(2pai+pai+pai/6)=1/2 sin(-16π/3)=-sin(4pai+pai+1/3pai)=根号3/2
cos(-79π/6)=cos(79pai/6)=cos(12pai+pai+pai/6)=-根号3/2 tan(-26π/3)=-tan(8pai+2pai/3)=-tan(pai-pai/3)=tan(pai/3)=根号3 sin(15π/4)=sin(4pai-pai/4)=-sin(pai/4)=-根号2/2
cos(-60°)-sin(-210°)=1/2+sin210=1/2-1/2=0
cos(-79π/6)=cos(79pai/6)=cos(12pai+pai+pai/6)=-根号3/2 tan(-26π/3)=-tan(8pai+2pai/3)=-tan(pai-pai/3)=tan(pai/3)=根号3 sin(15π/4)=sin(4pai-pai/4)=-sin(pai/4)=-根号2/2
cos(-60°)-sin(-210°)=1/2+sin210=1/2-1/2=0
sin(-21π/4) cos(-20π/3) tan(-19π/6)=
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