n(n-1)(n-2)(n-3)=120,求n.求计算过程,谢谢.
数学题目:lim(n趋向无穷大) ((n+1)*(n+2)*(n+3))/(3*n*n) =1/3的计算过程 急需,谢谢
若n²+3n=1,求n(n+1)(n+2)+1的值.
1\n(n+3)+1\(n+3)(n+6)+1\(n+6)(n+9)=1\2 n+18 n为正整数,求n的值
求极限Xn=n/(n^2+1)+n/(n^2+2)+n/(n^2+3)+……+n/(n^2+n),
y∧2n=3,试求x∧6n×y∧4n和(xy)∧(6n+4n)详细过程谢谢
数列a(n)=n (n+1)(n+2)(n+3), 求S(n)怎么用高中数列原理解答?
计算:n(n+1)(n+2)(n+3)+1
求极限lim [ 2^(n+1)+3^(n+1)]/2^n+3^n (n→∞)
求极限 n趋向无穷 2^n+1 + 3^n+1/2^n+3^n
求极限 lim(n->无穷)[(3n^2-2)/(3n^2+4)]^[n(n+1)]
求lim(n+1)(n+2)(n+3)/(n^4+n^2+1)
求(1^n+2^n+3^n)^1/n,n趋于无穷大的极限