好几个简便计算1.25×0.25×3232×9.1((1+0.12++0.23)×(0.12+0.23+0.34)-(1
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/09/15 00:48:07
好几个简便计算
1.25×0.25×3232×9.1
(
(1+0.12++0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)
1.25×0.25×3232×9.1
(
(1+0.12++0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)
1)
1.25×0.25×3232×9.1
= 1.25×0.25×8×4×101×9.1
=(1.25×8)×(0.25×4)×(101×9.1)
=10×1×919.1
= 9191
2)
(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)
假设A = 0.12+0.23
原式 = (1+A)×(A+0.34)-(1+A+0.34)×A
= A×A+A+0.34A+0.34-A-A×A-0.34A
= 0.34
1.25×0.25×3232×9.1
= 1.25×0.25×8×4×101×9.1
=(1.25×8)×(0.25×4)×(101×9.1)
=10×1×919.1
= 9191
2)
(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)
假设A = 0.12+0.23
原式 = (1+A)×(A+0.34)-(1+A+0.34)×A
= A×A+A+0.34A+0.34-A-A×A-0.34A
= 0.34
计算.要简便 (1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.
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