化简sinθ+cos(θ+2π/3)+cos(θ+4π/3)
已知 sin(θ+kπ)=-2cos (θ+kπ) 求 ⑴4sinθ-2cosθ/5cosθ+3sinθ; ⑵(1/4)
已知(4sinθ-2cosθ)/(3sinθ+5cosθ)=6/11,求5cos^2θ/(sin^2θ+2sinθcos
①化简[sin(2π+α)*cos(7π-α)]/cos(-α)②已知cosθ=-3/5,θ∈(π/2,π),求sin(
θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小
sin(π-θ)+cos(2π-θ)/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=_____
化简sin(θ-5π)cos(π/2+θ)cos(4π-θ)/cos(3π-θ)sin(θ-3π)sin(-θ-4π)
化简:1+sinθ+cosθ+2sinθcosθ /1+sinθ+cosθ
sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)
化简[cot(θ+4π)cos(θ+π)sin²(θ+3π)]/[tan(π+θ)cos²(-π-θ
已知tanθ=3,求(3cosθ-5sin^2θcosθ)/sin(π-θ)的值
已知向量m=(cosθ,-sinθ),n=(根号2+sinθ,cosθ),θ∈(π,3π/2),且cos(θ/2+π/8
三角函数化简[2cos^3θ+sin^2(π-θ)+sin(π/2+θ)-3]/[2+2cos^2(π+θ)+cos(-