作业帮一道高数题不定积分的谢谢回答
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/07/13 17:04:06
一道高数题不定积分的谢谢回答
∫3/（x^3+1)dx
∫3/（x^3+1)dx
∫3/(x^3+1)dx
=∫(x^2-x+1)+(x+1)-(x^2-1)/(x+1)(x^2-x+1)
=∫dx/(x+1)+∫dx/(x^2-x+1)-∫(x-1)/(x^2-x+1)dx
=∫dx/(x+1)-1/2∫(2x-1-1)/(x^2-x+1)+∫dx/(x^2-x+1)
=∫dx/(x+1)-1/2∫(x^2-x+1)/(x^2-x+1)+3/2∫dx/(x^2-x+1)
=ln|x+1|-(1/2)ln|x^2-x+1|+√3 arctan[(2x-1)/√3]+c
=∫(x^2-x+1)+(x+1)-(x^2-1)/(x+1)(x^2-x+1)
=∫dx/(x+1)+∫dx/(x^2-x+1)-∫(x-1)/(x^2-x+1)dx
=∫dx/(x+1)-1/2∫(2x-1-1)/(x^2-x+1)+∫dx/(x^2-x+1)
=∫dx/(x+1)-1/2∫(x^2-x+1)/(x^2-x+1)+3/2∫dx/(x^2-x+1)
=ln|x+1|-(1/2)ln|x^2-x+1|+√3 arctan[(2x-1)/√3]+c