(x-1)(x-2)(x-3)(x-4)=0
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
(x-1)^3(x+1)(x-2)/(x+4)
(x+1)(x+2)(x+3)(x+4)+1
x²+3x-1=0,1/(x-2)×(x²-4x+4)/(x+1)-(x-1)/(x+2)
(x-2)²=(2x-3)² x²-4x=0 3x(x+1)=3x+3 x²-2
已知(x-根号2+1)(x-3)=0,求代数式{[(x-1)/(x-3)]-[(x-4)/x]}/[(x的平方+x-6)
(x+2/x+1)-(x+4/x+3)-(x+3/x+2)+(x+5/x+4)
(x+1分之x+6)-(x^+3x+2分之3x^+10x+4)+(x+2分之2x+1)=0,解这个方程
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
解方程:(x-8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)
若1+x+x*x+x*x*x=0,求x+x*x+x*x*x+.+x(2000次幂)
3/x-1=4/x 6/x+1=x+5/x(x+1)