S
由S1=a1=1, S4 S2=4, 得到 4+6d 2+d=4,解得d=2, 则 S6 S4= 6a1+15d 4a1+6d= 36 16= 9 4. 故选A
已知等差数列{an}的前n项和为Sn,若S33−S1=1,则数列{an}的公差是( )
设数列an的前n项和为Sn,已知S1=1,Sn+1/Sn=n+c/n,且a1,a2,a3成等差数列
等比数列{an}的前n项和为Sn,已知S1,S3,S2成等差数列
等比数列{an}的前n项和为Sn,已知S1,S3,S2成等差数列
已知首项为1的等比数列{an}的前n项和为Sn,且S1,S2,S3成等差数列,则Sn等于
已知等差数列{an}、{bn}的前n项和分别为Sn、Tn,若Sn/Tn=【7n+1】/【4n+27】,则an/bn=
设数列an的前n项和为sn,已知s1=1,sn分之sn+1=n分之n+c且a1,a2,a3为等差数列.求c的值.
等比数列{an}的前n项和为Sn,已知S1,S3,S2成等差数列,求{an}的公比Q.已知a1-a3=3,求sn?
等比数列{an}的前n项和为Sn,已知S1,S3,S2成等差数列,求{an}的公比q
已知公差为d的等差数列an,其前n项和为Sn.等比为q的等比数列bn,其前n项和为Tn.已知a1=b1=1,S1+Sn\
已知等差数列{an}的前n项和为Sn,且a1不等于0,求(n*an)/Sn的极限、(Sn+Sn+1)/(Sn+Sn-1)
数列an是首项为3公差为2的等差数列其前n项和为Sn求An=1/S1+1/S2+1/S3+...+1/Sn
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