18/X -3 =18/X+1
计算1/[x(x+3)]+1/[(x+3)(x+6)]+.+1/[(x+15)(x+18)]=?
已知 X=4- 根号3 求 (X*X*X*X-6X*X*X-2X*X+18X+23) / (X*X-8X+15)的值
1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=3/2x+18
(X-X*20%-18-(X-X*20%-18)*10%=X*1/2-3(过程)
(x-3)(x-2)+18=(x+9)(x+1),X是多少啊?
0.75x-1/2x=-5;3x+5=4x+1;3X+5=4X+18;1-7x=x-7;9x+8-7x=3x;-(x-2
x+2/3x=60 x-3/5x=120 4x+18x=1
已知集合A={x/ x^2+3x-18>0},B={x/ (x-k)(x-k-1)=
知集合A={x/ x^2+3x-18>0},B={x/ (x-k)(x-k-1)=
x²-3x-18<0 (x-1)(x+2)=(x-2)(2x+1)
x(x-1)=18
3x²-(x-2)=0 (2x-1)(x+3)=4 x²-3x-4=0 x²-3x+18=