若lim x趋向0,（xcosα-sinα）/2x^3拆成(xcosα/2x^3)-(sinα/2x^3)那分子能用无穷

(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x x趋向于无穷时 lim (3x-1)/(x^3 乘以 sin(1/x^2 )) x趋于0时,lim(x^2-sin^2 xcos^2 x)/(x^2sin^2 x)怎么转换成(x^2-(1/4)sin 已知函数f(x)=sin^2ωx+√3cosωxcos(π/2-ωx)(ω>0) sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x) =sin^4x-sin^2xcos lim xcos(1+X^2)/sinx x趋向于0 求极限 当x趋向π lim (sin 3x )/( sin 2x) 的极限为? 求不定积分(1/sin^2xcos^2x)dx 求不定积分,∫sin^2xcos^2x dx 求lim (sin^2x+x)/(cos^2x-x) x趋向于无穷 已知函数f(x)＝2sinωxcosωx+23sin2ωx−3（ω＞0）的最小正周期为π． lim(x趋向无穷)[1-(2/x)]^3x