(8-2x)×2\5+(x+3)×36%+0.35x+38.5%×11

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/07/14 06:28:31

(8-2x)×2\5+(x+3)×36%+0.35x+38.5%×11
对不起，题出错了。应该是：
(8-2x)×2\5+(x+3)×36%+0.35x=
38.5%×11

(8-2x)×2\5+(x+3)×36%+0.35x+38.5%×11=8×2/5-2x×2/5+x×36%+3×36%+0.35x+4.235
=3.2-0.8 x+0.36x+1.08+0.35x+4.235
=(3.2+1.08+4.235)+(-0.8 x+0.36x+0.35x)
=8.515-0.09x
再问：啊啊
再答：哇哇哇哇，哎，算了。
(8-2x)×2\5+(x+3)×36%+0.35x=38.5%×11
8×2/5-2x×2/5+x×36%+3×36%+0.35x=4.235
3.2-0.8x+0.36x+1.08+0.35x=4.235
-0.8x+0.36x+0.35x=4.235-3.2-1.08
-0.09x=-0.045
x=(-0.045)÷(-0.09)
x=0.5

|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550 x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少? 化简：9x-12x+5x,3x-5x-2+5x+8,3x+5+2x+3-7-11x (2x-1)/(x-1)(x-2)=(x-5)/(x-2)(x-3) x/2x^2-11x-21=(x+7)/x^2-1 已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^5+x^6+x^7+x^8的值 [1/(x-1)(x+2)]+[1/(x+2)(x+5)]+[1/(x+5)(x+8)]+[1/(x+8)(x+11)] y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1 设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10), 求x^2-3x/x^2-6x+9*x^2-11x+30/x^2-5x-1 (3-x)/(1-x)-(5-x)/(7-x)+(x^2-x)/(x^2-8x+7)=1 解方程:(x+3)/(x+2)-(x+5)/(x+4)=(x+7)/(x+6)-(x+9)/(x+8)