1.已知tanX=2,求:(tan2X—tanX)/(1+tan2X tanX)的值.
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/08/24 04:22:00
1.已知tanX=2,求:(tan2X—tanX)/(1+tan2X tanX)的值.
2.化简:sin(X—Y)cosY+cos(X—Y)sinY
3.cos80°sin50°—sin40°sin80°=?
4.若X,Y为锐角,且sinX=(12/13),sinY=(3/5),则sin(X+Y)的值为?
5.计算(1)sin15°cos15° ;(2)2(cos^2 )* (π/8) —1
6.已知cosX=(1/5),(3π/2)
2.化简:sin(X—Y)cosY+cos(X—Y)sinY
3.cos80°sin50°—sin40°sin80°=?
4.若X,Y为锐角,且sinX=(12/13),sinY=(3/5),则sin(X+Y)的值为?
5.计算(1)sin15°cos15° ;(2)2(cos^2 )* (π/8) —1
6.已知cosX=(1/5),(3π/2)
(tan2X—tanX)/(1+tan2X tanX)
=tan(2X—X)
=tanX
=2
sin(X—Y)cosY+cos(X—Y)sinY
=sin(X—Y+Y)
=sinX
cos80°sin50°—sin40°sin80°
=cos80°(sin90°-40°)—sin40°sin80°
=cos80°cos40°—sin80°sin40°
=cos(80°+40°)
=cos120°
=-1/2
X,Y为锐角,且sinX=(12/13),sinY=(3/5)
cosX=5/13,cosY=4/5
sin(X+Y)
=sinXcosY+cosXsinY
=12/13*4/5+5/13*3/5
=48/65+15/65
=63/65
sin15°cos15°
=1/2sin30°
=1/2*1/2
=1/4
2(cos^2 )* (π/8) —1
=cos(2*π/8)
=cos(2*π/8)
=cosπ/4
=√2/2
cosX=(1/5),(3π/2)
=tan(2X—X)
=tanX
=2
sin(X—Y)cosY+cos(X—Y)sinY
=sin(X—Y+Y)
=sinX
cos80°sin50°—sin40°sin80°
=cos80°(sin90°-40°)—sin40°sin80°
=cos80°cos40°—sin80°sin40°
=cos(80°+40°)
=cos120°
=-1/2
X,Y为锐角,且sinX=(12/13),sinY=(3/5)
cosX=5/13,cosY=4/5
sin(X+Y)
=sinXcosY+cosXsinY
=12/13*4/5+5/13*3/5
=48/65+15/65
=63/65
sin15°cos15°
=1/2sin30°
=1/2*1/2
=1/4
2(cos^2 )* (π/8) —1
=cos(2*π/8)
=cos(2*π/8)
=cosπ/4
=√2/2
cosX=(1/5),(3π/2)
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