(sinx-1)tanx怎么化简成[(sinx-sinπ/2)/sin(x+π/2)]sinx,x趋于π/2
化简{sin(π+x)}/1+cos(3π-x)根号下(tanx-sinx)/(tanx+sinx)
已知sinx+cosx7/13,且0<x<π. (1)求sinx,cosx,tanx的值; (2)求sin²x
已知sin² 2x+sin2xcosx-cos2x=1, x∈(0,2/π),求sinx,tanx
|sin(x+π/2)|-|sinx|求导过程?
化简f(x)=4sinx*sin^2((π+2x)/4)+(cosx+sinx)(cosx-sinx)
2sin(x-π/4)sin(x+π/4)=(sinx-cosx)(sinx+cosx)=-cos2a
已知(sinx+cosx)/(sinx-cosx)=3,求tanx,2sin²x+(sinx-cosx)&su
求化简(sinx+tanx)/cos^2x+sin^2x+cosx
已知sinx+cosx=1/5 求2sinx*cosx+2sin²x/1-tanx
(sin^x/sinx-cosx)-sinx+cosx/tan^2x-1
f(x)=cos(2x-π/3)+2sin(x-π/4)怎么化简成(sinx-cosx)(sinx+cosx)
(1+tanx)/(1-tanx)=3+2根号2,求(sin x+cosx)^2-(cos^3x)/sinx