若[sin(π-θ)+cos(2π-θ)]/[cos(5π/2-θ)+sin(3π/2+θ)]=2,求sinθ*cosθ
已知 sin(θ+kπ)=-2cos (θ+kπ) 求 ⑴4sinθ-2cosθ/5cosθ+3sinθ; ⑵(1/4)
θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小
已知tanθ=3,求(3cosθ-5sin^2θcosθ)/sin(π-θ)的值
若(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)等于?
已知(4sinθ-2cosθ)/(3sinθ+5cosθ)=6/11,求5cos^2θ/(sin^2θ+2sinθcos
sin(π-θ)+cos(2π-θ)/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=_____
(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)=
①化简[sin(2π+α)*cos(7π-α)]/cos(-α)②已知cosθ=-3/5,θ∈(π/2,π),求sin(
1.已知2sin(3π+θ)=cos(π+θ),求2sin
2sinθ+cosθ/sinθ-3cosθ=-5,求cos2θ+4sinθ
已知tan(θ+π/4)=-2,求cosθ平方+sinθcosθ-1
已知2sinθ+3cosθ=2,求sinθ+cosθ的值