已知根号x=根号2-1/根号2,根号y=根号3-1/根号3,求代数式【(x+y)/(根号x-根号y)】-
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/07/16 16:26:54
已知根号x=根号2-1/根号2,根号y=根号3-1/根号3,求代数式【(x+y)/(根号x-根号y)】-
求代数式【(x+y)/(根号x-根号y)】-2xy/(x根号y-y根号x)
已知根号x=根号2-(1/根号2),根号y=根号3-(1/根号3),求代数式【(x+y)/(根号x-根号y)】-2xy/(x根号y-y根号x)
求代数式【(x+y)/(根号x-根号y)】-2xy/(x根号y-y根号x)
已知根号x=根号2-(1/根号2),根号y=根号3-(1/根号3),求代数式【(x+y)/(根号x-根号y)】-2xy/(x根号y-y根号x)
【(x+y)/(根号x-根号y)】-2xy/(x根号y-y根号x)
=(x+y)/(√x-√y)-2xy/(x√y-y√x)
=(x+y)/(√x-√y)-2xy/{[√(xy)](√x-√y)}
=(x+y)/(√x-√y)-2√(xy)/(√x-√y)
=[x+y-2√(xy)]/(√x-√y)
=√x-√y=√2-1/√2-√3+1/√3
=(x+y)/(√x-√y)-2xy/(x√y-y√x)
=(x+y)/(√x-√y)-2xy/{[√(xy)](√x-√y)}
=(x+y)/(√x-√y)-2√(xy)/(√x-√y)
=[x+y-2√(xy)]/(√x-√y)
=√x-√y=√2-1/√2-√3+1/√3
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