设数列{an}满足a(n+1)=2an+n^2-4n+1若a1=3,求证:存在f(n)=an^2+bn+c(a,b,c为
在数列an中a1=2,a(n+1)下标=4an-3n+1 1设bn=an-n求证bn是等比数列 2求数列an的前n项和s
已知数列an,bn满足a1=1,a2=3,(b(n)+1)/bn=2,bn=a(n+1)-an,(n∈正整数)
已知数列(An)中,A1=1/3,AnA(n-1)=A(n-1)-An(n>=2),数列Bn满足Bn=1/An
已知数列{an}满足a1+a/4,(1-an)a(n+1)=1/4,令bn+an-1/2 求证数列{1/bn}为等差数列
已知数列{An}与{Bn}满足:A1=λ,A(n+1)=2/3An+n-4,Bn=(-1)^n*(An-3n+21),其
数列{an} {bn}满足:a1=0 a2=1 a(n+2)=[an+a(n+1)]/2 bn=a(n+1)-an 求证
已知数列{an}{bn}满足a1=1,a2=3,b(n+1)/bn=2,bn=a(n+1)-an,(n∈正整数),求数列
在数列{an}中,已知a1=-1,an+a(n+1)+4n+2=0 (1)求bn=an+2n,求证:{bn}为等比数列
数列an中,a1=1,a2=2数列bn满足an+1+(-1)n次an,a属于N* (1)若an等差数列...
设数列an前n项和为sn,an=5sn+1 bn=(4+an)/(1-an),记cn=b(2n)-b(2n-1),求证c
快,数列{An}的前n项和为Sn,a1=1,S(n+1)=4An+2,若Bn=A(n+1)-2An,求1,Bn?2,若C
已知数列{an}的前n项和为Sn,a1=1,a(n+1)=1+2Sn.设bn=n/an,求证:数列{bn}的前n项和Tn