x/(1+x)+y/(1+y)+z/(1+z)=1 求证x+y+z大于等于2(xy+yz+zx)
xy+yz+zx=1,x,y,z>=0
(1/x+1/y+1/z)×(xy)/(xy+yz+zx)
xy+yz+zx=1,求x√yz+y√zx+z√xy
已知X,Y,Z都是整数且xy+yz+zx=1,求证x+y+z>=根号3
分解因式:xyz-yz-zx-xy+x+y+z-1
已知xy:yz:zx=3:2:1,求①x:y:z ②x/yz:y/zx
已知xy/x+y=3,yz/y+z=2,zx/z+x=1,求y的值
已知x,y,z都是正数,且xyz=1,求证:xy(x+y)+yz(y+z)+zx(z+x)》6
X+Y/XY=1,Y+Z/YZ=2,Z+X/ZX=3 求X的值
x+y分之xy=1,y+z分之yz=2,z+x分之zx=3
已知x+y+z=1,x²+y²+z²=2求xy+yz+zx
设x,y,z为正实数,x+y+z=1.求证:yz/x+zx/y+xy/z+9xyz>=1+x^2+y^2+z^2