解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
1x()+2x()+3x()+4x()+5x()+6x()+7x()+8x()加9x()+10x()=1980
1X?+2X?+3X?+4X?+5X?+6X?+7X?+8X?+9X?+10X?=1980求?是多少
C语言中编写s=1-x+(x*x)/2!-(x*x*x)/3!+(x*x*x*x)/4!知道最后一项的绝对值小于10的-
求函数y=\x-1\+\x-2\+\x-3\+\x-4\+\x-5\+\x-6\+.+\x-10\的最小值
解方程:(2x+5)(4x*x-10x+25)=8x(x*x+1)
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
f(x)=1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+.1/(x+9)(x+10) 求
( A/X-5 ) + ( B/X+2 ) = 5X-4/X^2-3X-10 ^-^