In the standard(x,y) coordinate plane,what is the equation o

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In the standard(x,y) coordinate plane,what is the equation of the line whose points are equidistant from the
points (2,4）and (-4,6)?
A.5x-y=10 B.3x+y=2 C.3x-y=-8 D.x-3x=16 E.x+3y=14

选C
在标准的（x,y）坐标平面,从点（2,4）和点（-4,6）等距的线方程是什么?
点（2,4）和点（-4,6）中点是【（2-4）/2,（4+6）/2】=（-1,5）,方程是y=-1/3x+22/3
与y=-1/3x+22/3垂直的方程,k=3,设y=3x+b
经过点（-1,5）,则b=8
所以y=3x+8,即3x-y=-8

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