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计算:{(2/3x²)-2/(x²+y²)【(x²+y²/3x

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/07/18 13:34:32
计算:{(2/3x²)-2/(x²+y²)【(x²+y²/3x²)-x²-y
计算:{(2/3x²)-2/(x²+y²)【(x²+y²/3x²)-x²-y²)】}÷(x²-y²)/x²
{(2/3x²)-2/(x²+y²)【(x²+y²/3x²)-x²-y²)】}÷(x²-y²)/x²
={(2x²+2y²-6x²)/[3x²(x²+y²)][(x²+y²-3x²(x²+y²)/3x²]*x²/(x²-y²)
=(2y²-4x²)/[3x²(x²+y²)][(x²+y²)(1-3x²)/3x²]*x²/(x²-y²)
=(2y²-4x²)(1-3x²)/3x²(x²-y²)
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再答: {(2/3x²)-2/(x²+y²)【(x²+y²/3x²)-x²-y²)】}÷(x²-y²)/x² ={(2/3x²)-2/(x²+y²)[(x²+y²-3x²(x²+y²)/3x²]*x²/(x²-y²) ={(2/3x²)-2/(x²+y²)[(x²+y²)(1-3x²)/3x²]*x²/(x²-y²) =[2/3x²-(2-6x²)/3x²]*x²/(x²-y²) =6x²/3x²*x²/(x²-y²) =2x²/(x²-y²)