x+y=12 y+z=20 z+x=18 求X Y Z分别等于几?
已知X+Y=12 Y+Z=10 求X Y Z各等于几
三元一次方程组,x+y+z=26x-y=12x-y+z =18 求x,y,z各等于几
(x+y-z)(x-y+z)=
x y z x+y--- = --- = ---- ----y+Z z+x x+y ,求 z 的值 .求 x+y----
x+y=10 y+z=15 z+x=20 求x,y,z等于多少?
解方程组{x(x+y+z)=6,y(x+y+z)=12,z(x+y+z)=18
已知x+y-z/z=x-y+z/y=-x+y+z/x,且xyz不等于0,求分式[(x+y)(x+z)(y+z)]/xyz
若z分之x+y+z=y分之x-y+z=x分之-x+y+z,求xyz分之(x+y)(y+z)(z+x)
y+z÷x=Z+X÷y=X+Y÷z,X+Y+Z不等0求X+Y-Z÷X+Y+z值
(x+y-z)/z=(y+z-x)/x=(z+x-y)/y 求(x+y)(y+z)(z+x)/xyz
x分之y+z=y分之z+x=z分之x+y(x+y+z不等于0),求x+y+z分之x+y-z
已知:(x+y-z)/z=(x-y+z)/y+(y+z-x)/x,且xyz≠0,求代数式[(x+y)(y+z)(x+z)