lim(x->0)(ln(1+x)-x)/(cosx-1)=?
lim(x→0)(cosx)^(1/ln(1+x^2))
lim(x→0)(ln(1+x^2)/(sec-cosx))
lim[ln(1+x^2)]/(secx-cosx) x->0
lim(x->0)[cosx-e^(-x^2/2)]/[x^2[x+ln(1-x)]]
lim x趋于0 (sinx+x^2sin1/x)/[(1+cosx)ln(1+x)]
lim(x→0)(x^2+cosx-2)/(x^3)*ln(1+x)怎么算
lim(x→0) (ln cosx)/[ln(1+x^2)] 等于多少?
1、lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx
求 lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx
lim(x趋于0)(1-cosx)/[ln(1+x)(e^x-1)]
lim(1-cosx)/(e^x-1)ln(1-x),x->0
x趋向于0,lim[x*ln(1+3x)]/(1-cosx)