log2(8-2x-x^2)≤3 ~~~~~~~~~~~~~~~~~~~~~~
|2x-log2^x|
不等式log2(2x+3)>log2(x+1)的解集是
log2 (x + 3) + log2(x + 2) = 1
解方程log2(x+14)-log2(x+6)=3-log2(x+2)
log2(x)=-2/3,求x
已知x满足不等式2[log2(x)]^2-7[log2(x)]+3≤0,求函数f(x)=[log2(x/2)]*[log
解不等式log2(5x^2-8x+4)>3
解不等式log2^(5x^2 -8x +4) >3
已知x满足不等式2(log1/2 x)^2+7log1/2 x+3≤0.f(x)=(log2 x/4)^2(log2 x
已知满足不等式2log2(x)-7log2(x)+3≤0,求函数f(x)=[log2﹙x/2﹚][log2﹙x/4﹚]的
解不等式Log2(4+3x-x^2)>log2(4x-2)
高一不等式,要过程(1) log2(x加5)>log2(3-x) (2) 2^x