(1)(x+2)(x²-2x)=x³-8
解方程 x(x+1)(x²-2x-4)=0 x³-2x+1=0 x的4次方+8x³+14x
解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1
(4x³)²×[x³-x(2x-1)]
(2x²-2x+3)(-x³+x-1)
2f(x)+x^2f(1/x)=(3x³-x²+4x+3)/(x+1) 2x²f(1/x)
先化解,在求值;(3x/x-1-x/x+1)÷x四次方-4x²/x³-x,其中x=根号2+2
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
x/2+x/8+x/12+x/20=1
X-5+8*X=7*X-2*X-1
3X+(X+2)+(X+1)*(X-1)=4*(X²+8)
已知 X=4- 根号3 求 (X*X*X*X-6X*X*X-2X*X+18X+23) / (X*X-8X+15)的值
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1