(2x-5)²+(3x+1)²>13(x²-10)
x(2x-1)=-3x(x+1)+5x²+3
x(x²-1)+2x²(x+1)-3x(2x-5)计算
(x-2)(x-3)+2(x+6)(x-5)-3(x²-7x+13)化简
5x²+[x²+(5x²-2x)]-2(x²-3x),其中x=-1
((x²-5x+6)/(12-7x+x²))²÷((x²+3x+2)/(x
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
计算:[(-5+x)(-x-5)]² (x+3)²-(x+2)(x-1) (3x-a)(3x+a)(
6x+(2x²-3x)-(x²-1)
(2x²-2x+3)(-x³+x-1)
3x²-[5x-(x-2)+2x²]其中x= -1/2
x(3x² -5x+1)-3x² (x-2)
代数式6x+2x²-3x+x²+1,其中x=-5