6.0 of ammonium phosphate is dissolved into water to produce

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6.0 of ammonium phosphate is dissolved into water to produce 300mL of solution.What are the concentrations (in mol/L) of the ammonium ions and phosphate ions present?我是加拿大高中生.大概中文就是有6克(NH4)2PO4融化在300毫升水里,求nh4离子和po4离子的concentration.

M[(NH4)3PO4] = 149 g/mol
m[(NH4)3PO4] = 6 g
n[(NH4)3PO4] = m[(NH4)3PO4]/M[(NH4)3PO4] = 6 g/149 g/mol = 0.04 mol
V[(NH4)3PO4(ag)]=300 mL=0.3 L
(NH4)3PO4 = 3NH4^+ + PO4^3-
c(NH4^+) = n(NH4^+)/V[(NH4)3PO4(ag)] = 3*0.04 mol / 0.3 L = 0.4 mol/L
c(PO4^3-) = n(PO4^3-)/V[(NH4)3PO4(ag)] = 0.04 mol / 0.3 L = 0.13 mol/L

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