快!坐等 ~~~~ 如图 AB=DE BC=EF CD=FA ∠A=∠D 求证:∠ABC=∠DEF
已知:AB||DE,∠ABC+∠DEF=180°,求证BC||EF 快....
如图,已知AF‖CD∠BAF=∠CDE∠ABC=∠DEF求证AB‖DE,BC‖EF急急急,1小时之内,
如图,AB=BC=CD=DE=EF,∠DEF=4∠A,求∠A
已知:如图,AB=DE,BC=EF,AF=CD,求证∠A=∠D
如图,△ABC中,AB=AC,若BC=CD=DE=EF=FA,则∠A=______°.
已知:AB||DE,∠ABC+∠DEF=180°,求证BC||EF
如图,已知∠A=∠D,AB=DE,AF=CD,BC=EF. 求证:BC‖EF
如图,已知∠A=∠D,AB=DE,AF=CD,BC=EF.求证:BC∥EF.
已知:AB=DE,BC=EF,CD=AF,∠A=∠D,试说明:∠ABC=∠DEF
如图,AB=DE,BC=EF,CD=FA,角A等于角D.求证:角b=角e
如图,AB=DE,AC//DF,BC//EF,求证:△ABC≌△DEF
1.如图,AB=DE,AC//DF,BC//EF,求证:△ABC≌△DEF.