(2+7/9)^0.5+(2+10/27)^2/3-(27/125)^(-1/3)

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/11/09 09:27:22

(2+7/9)^0.5+(2+10/27)^2/3-(27/125)^(-1/3)
=(25/9)^0.5+(64/27)^2/3-(27/125)^(-1/3)
=5/3+16/9-5/3
=16/9

(0.027)^3/2+(27/125)^-1/3-(2又7/9)^0.5 求值根号2-1-2^0.5+3×0.6^1/2×(27/125)^-1/6 , 计算[2(7/9)]^0.5+0.1^-2+[2(10/27)]^(-2/3)-3π^0+37/48 1、计算下面各题 4/5÷0.5×3/7 (7/10-1/2)×9/20 2-27/28÷9/14 1=2,3+5=8,7+9+11=27,13+15+17+19=64,21+23+25+27+29=125 (n^2-n 4,3/2,20/27,7/16,36/125,( 4,3/2,20/27,7/16,36/125,( ) 4.4,3/2,20/27,7/16,36/125,( ) 4,3/2,20/27,7/16,36/125,() (49/9-0.8+23/9)*125怎么简算?还有4/3+4/7+11/3+2/27+3/7+7/27怎样简算? 1+2+3-4+5+6+7-8+9+10+11-12+.+25+26+27-28 11*10*9*8*7*6*5*4*3*2*1/(22*24*25*27)