x2+4y2-6x+4y+10=0,求x,y的值;求x2+y2的值(因式分解)
1.已知X2+Y2-4X-6Y+13=0,求Y2-X2的值
已知x2-4x+y2-6y+13=0求x2+y2的值?
已知X2+Y2+8X+6Y+25=0 求代数式X2++XY+4Y2分之X2-4Y2 减X+2Y分之X的值
若X2+Y2-2X-6Y+10=0 ,求(x2-y2)/xy的值
已知x2+y2-4x+6y+13=0,求x2-6xy+9y2的值.
已知X2-2x+y2+6y+10=0,求(x2-2xy)/(xy+y2)的值
已知x2-4x+y2+6y+13=0,求x-y的值
已知2x=3y,求xy/(x2+y2)-y2/(x2-y2)的值
已知x,y为实数,且(x2 +y2)(x2 +y2+2)=3.求x2 +y2的值
已知实数x.y满足(x2+y2)(x2+y2-1)=2,求x2+y2的值
已知x2+y2-10x-6y+34=0,求y\x+y的值
已知x2+y2-10x-6y+34=0,求(x-y/x+y)2÷x2-y2/xy×x2+2xy+y2/x2-xy 的值.